If $x$ and $y$ are distinct integers, then which of the following is true about $\frac{x + y}{2}$ ?

It is less than $x$ and greater than $y$

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It is greater than both $x$ and $y$

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It is less than both $x$ and $y$

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It lies between $x$ and $y$

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Solution

The correct option is D
It lies between $x$ and $y$

$\frac{x + y}{2}$ shows the average of two numbers $x$ and $y$ . We know that average of any two numbers lies between the given numbers. So, the value of $\frac{x + y}{2}$ lies between $x$ and $y$ .

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Similar questions

If x and y are distinct integers, which of the following is true about $\frac{x + y}{2}$ ?

If $x$ and $y$ are distinct rational numbers which of the following is true about $\frac{x + y}{2}$ ?

Question 24
$\frac{x + y}{2}$ is a rational number
(a) Between x and y
(b) Less than x and y both.
(c) Greater than x and y both.
(d) Less than x but greater than y.

Question 24
$\frac{x + y}{2}$ is a rational number
(a) Between x and y
(b) Less than x and y both.
(c) Greater than x and y both.
(d) Less than x but greater than y.

In the following question, two equations are given. Solve both the equations and mark the corresponding answer, if:

a) x is greater than y

b) x is less than y

c) x is greater than or equal than y

d) x is less than or equal to y

e) x = y or a definite relationship between x & y cannot be established

2x $^{2}$ + 3x + 1 = 0

12y $^{2}$ + 7y + 1 = 0

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If x and y are distinct integers, then which of the following is true about x+y2 ?

The correct option is D It lies between x and y x+y2 shows the average of two numbers x and y. We know that average of any two numbers lies between the given numbers. So, the value of x+y2 lies between x and y.

If $x$ and $y$ are distinct integers, then which of the following is true about $\frac{x + y}{2}$ ?

The correct option is D
It lies between $x$ and $y$

$\frac{x + y}{2}$ shows the average of two numbers $x$ and $y$ . We know that average of any two numbers lies between the given numbers. So, the value of $\frac{x + y}{2}$ lies between $x$ and $y$ .