If x and y are integers then the equation 5x+19y=64 has:
A
no solution for x < 300 and y < 0
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B
no solution for x > 250 and y > - 100
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C
a solution for 250 < x < 300
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D
a solution for -59 < y < -56
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Solution
The correct option is C a solution for 250 < x < 300 We see that if y = 1, we get an integer solution for x = 9, now if y changes (increases or decreases) by 5, x will change (decrease or increase) by 19.
Looking at options, if x = 256 we get y = - 64.
Using these values we see option 1, 2 and 4 are eliminated and also that there exists a solution for 250<x<300.