If x and y are positive integers, which of the following is equivalent to $(2 x)^{3 y} - (2 x)^{y}$ ?

(2 x)^{2 y}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2^{y} (x^{3} - y^{y})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 x)^{y} [(2 x)^{2 y} - 1]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2 x)^{y} (4 x - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 x)^{y} [(2 x)^{3} - 1]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(2 x)^{y} [(2 x)^{2 y} - 1]$
$(2 x)^{3 y} - (2 x)^{y} = (2 x)^{y} [(2 x)^{2 y} - 1]$

Suggest Corrections

Similar questions

Multiply the terms $- 3 x^{2} y^{2}, - 2 x y, 2 x^{2} y$ and verify the product for $x = 1$ and $y = 2$

\frac{x^{2} - y^{2}}{2 x^{2} y - 2 x y^{2}}

\frac{x + y}{2 x y}

1

0

(2 x y - y^{2} - y) d x = (2 x y + x - x^{2}) d y

Multiply the terms $- 3 x^{2} y^{2}, - 2 x y, 2 x^{2} y$ and verify the product for $x = 1$ and $y = 2$

y_{1} = \frac{y^{2} - 2 x y - x^{2}}{y^{2} + 2 x y - x^{2}}

(1, - 1)

Join BYJU'S Learning Program