If X and Y are two non- empty sets where f;X→Y is function is defined such that{ f(c)=y:c∈X} for c⊆X,y⊆Y and {f−1(D)=x:f(x)∈D} for D⊆Y for any x⊆X , then
The option b satisfied the above definition of function f so option (b) is correct. The option c is not correct because we can not prove that b has a pre image in c itself