Question

If x and y vary inversely and x = 18 when y = 8, find x when y = 16.

Answer 1

$x$	18	$x_1$
$y$	8	16

$$\begin{gathered} x\mathrm{and}y\mathrm{var}y\mathrm{inversely}. \\ \mathrm{i}.\mathrm{e}.xy=\mathrm{constant} \\ \mathrm{Now},18\times 8=x_1\times 16 \\ \Rightarrow \frac{18\times 8}{16}=x_1 \\ \Rightarrow 9=x_1 \end{gathered}$$

∴ Value of $x=9$