If $x = a s i n (ω t + \frac{π}{6})$ and $x = acoswt$ then what is the phase difference between the two waves?

$\frac{π}{3}$

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$\frac{π}{6}$

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$\frac{π}{2}$

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$π$

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Solution

The correct option is A
$\frac{π}{3}$

$x = a s i n (ω t + \frac{π}{6})$

$x^{'} = a c o s ω t = a s i n (ω t + \frac{π}{2})$

$∴ P h a s e d i f f e r e n c e = (π / 2) - (π / 6) = (π / 3)$

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Similar questions

x = a sin (ω t + π / 6)

y = a cos ω t

If $x = a s i n (ω t + \frac{π}{6})$ and $x = acoswt$ then what is the phase difference between the two waves?

x_{1} = A sin (ω t + \frac{π}{6})

x_{2} = A cos ω t

If $x = a s i n [ω t + \frac{π}{6}] a n d x^{'} = a c o s ω t$ , then what is the phase difference between the two waves?

x = a sin (ω t + π / 6)

x^{'} = a cos ω t

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