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Question

If X assumes value of 1.2 and 5 with the probability of 0.2,0.35 and 0.45 respectively. What is the expected value of X

A
3.20
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B
3.15
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C
.80
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D
3.25
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Solution

The correct option is B 3.15
According to the question, the probability distribution of variable X can be written as:
X 1 2 5
P(X) 0.2 0.35 0.45
The expected value of X is nothing but the mean of X, i.e., μ
Hence, μ=E(X)=ni=1xipi
μ=1×0.2+2×0.35+5×0.45=0.2+0.7+2.25=3.15

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