If x - y - -x2 - y2- then the value of 1- 2 -21- - 2 -2 is-

The correct option is D 9 1^∗ 2 √(2) = √((1)^2 + (2 √(2)^2) = √(1 + 8) = 3 1^∗ 2 √(2) = √((1)^2 + ( 2 √())^2) = √(1 + 8) = 3 (1 ∗ ...

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Roots of a Quadratic Equation

If x ∗ y = ...

Question

If $x * y = \sqrt{x^{2} + y^{2}}$ , then the value of $(1^{} 2 \sqrt{2}) (1^{} - 2 \sqrt{2})$ is:

- 7

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x \times y = \sqrt{x^{2} + y^{2}}

(1 \times 2 \sqrt{2}) (1 - 2 \sqrt{2})

x = 5 + 2 \sqrt{6}

y = 5 - 2 \sqrt{6}

\frac{1}{x^{2}} + \frac{1}{y^{2}}

x = {(2 + \sqrt{5})}^{1 / 2} + {(\sqrt{5} - 2)}^{1 / 2}

y = {(2 + \sqrt{5})}^{1 / 2} - {(\sqrt{5} - 2)}^{1 / 2}

x^{2} + y^{2}

x = \sqrt{2}

y = \frac{1}{\sqrt{2}}

(x^{2} - y^{2})

y = f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} \sqrt{x + 3}, & - 3 \leq x < - 2 1 + \sqrt{x + 2}, & - 2 \leq x < - 1 2 + \sqrt{x + 1}, & - 1 \leq x \leq 0 \end{matrix}

| y | = f (- | x |)

x^{2} + y^{2} = 5

p + π q

(p + q)

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