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Question

If xy=x2+y2, then the value of (122)(122) is:

A
- 7
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B
0
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C
2
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D
9
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Solution

The correct option is D 9
122=(1)2+(222=1+8=3

122=(1)2+(2)2=1+8=3

(122)(122)=(3)(3)=9

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