If x=b-c, y=c-a, z=a-b then the value of $x^{2} - y^{2} + z^{2} + 2 x z$ is

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Solution

The correct option is C 0
Given x=b-c ,y=c-a and z=a-b
Then $x^{2} - y^{2} + z^{2} + 2 x z$
= $(b - c)^{2} - (c - a)^{2} + (a - b)^{2} + 2 (b - c) (a - b) = b^{2} - 2 b c + c^{2} - c^{2} - a^{2} + 2 a c + a^{2} + b^{2} - 2 a b + 2 a b - 2 a c - b^{2} + 2 b c = 0$

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