If x be real, then the minimum value of $x^{2} - 8 x + 17$ is

-1

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Solution

The correct option is C
1

$x^{2} - 8 x + 17 = (x^{2} - 8 x + 16) + 1 = (x - 4)^{2} + 1$

Since x is real, so $(x - 4)^{2}$ is always non negative and its least value is 0 and so the minimum value of given expression is 1.

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