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Question

If x+1x=2cosθ, then for any integer n, xn+1xn is equal to

A
2cosnθ
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B
2sinnθ
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C
2icosnθ
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D
2isinnθ
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Solution

The correct option is B 2cosnθ
Let x=cosθ+isinθxn=cosnθ+isinnθ
Then, 1x=cosθisinθ1xn=cosnθisinnθ
xn+1xn=2cosnθ

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