Question

If $x^{\circ }={405}^{\circ }\text{and}{y}^c=-\frac{{\pi }^c}{12}$, Find the value of $\frac{x}{y}$

Answer 1

we know that ${\pi }^c={180}^{\circ }\Rightarrow {180}^{\circ }={\pi }^c$

$1^{\circ }=\frac{{\pi }^c}{{180}^{\circ }}$

$x^c={405}^{\circ }$

$=405\times \frac{\pi }{180}=\frac{9\pi }{4}$

given $y^c=\frac{-{\pi }^c}{12}$

$\therefore x=\frac{9{\pi }^c}{4}$

$\frac{x^c}{y^c}=\frac{9\pi /4}{-\pi /12}=\frac{-9\pi }{\pi }\times 3=-27$