If $x . c o s A = 1$ and $t a n A = y$ , then $x^{2} - y^{2}$ is equal to :

tan A

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1

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s i n A

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- tan A

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Solution

The correct option is B $1$
$x cos A = 1, tan A = y$
$\Rightarrow x = sec A$

Now, $x^{2} - y^{2} = {sec}^{2} A - {tan}^{2} A$
$= 1$
Hence, the answer is $1.$

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