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Question

If x=cosα+cosβcos(α+β) and y=4sinα2sinβ2cos(α+β2), then (xy) is equal to

A
1
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B
1
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C
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D
10
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Solution

The correct option is A 1
x=cosα+cosβcos(α+β)=2cosα+β2cosαβ2(2cos2α+β21)

=1+2cosα+β2(cosαβ2cosα+β2)

=1+4sinα2sinβ2cos(α+β2)

=1+y

xy=1

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