If x cos- - y cos 2 -3 - - - z cos 4 -3 - - - then xy - yz - zx -

The correct option is C 0 Let α = 0 Then x = y2 = z2 = k ...(constant) Hence x = k y = z = 2k Hence xy + yz + zx = 2k^2 ...

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Properties Derived from Trigonometric Identities

If x cosα =...

Question

If $x cos α = y cos (\frac{2 π}{3} + α) = z cos (\frac{4 π}{3} + α)$ , then $x y + y z + z x =$

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Similar questions

x = y cos \frac{2 π}{3} = z cos \frac{4 π}{3}

x y + y z + z x =

x = y cos \frac{2 π}{3} = z cos \frac{4 π}{3}

x = y cos \frac{2 π}{3} = z cos \frac{4 π}{3}

x y + y z + z x

x cos α = y cos (2 π / 3 + α) = cos (4 π / 3 + α),

x y + z y + z x =

x cos θ = y cos (120^{o} + θ) = z cos (θ + 240^{o})

x y + y z + z x = 1

cos α + cos (120^{o} + α) + cos (120^{o} - α) = 0

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