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Question

If x=cos θ+isin θ and y=cosϕ+isinϕ, then xmyn+xmyn ,is equal to

A
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C
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Solution

The correct option is C
x=cos θ+i sin θ=eiθ,y=cos ϕ+i sinϕ=eiϕ
xmyn+xmyn=eimθeinϕ+eimθeinϕ
=ei(mθ+nϕ)+ei(mθ+nϕ)=cos(mθ+nϕ)+i sin(mθ+nϕ)+cos(mθ+nϕ)i sin(mθ+nϕ)
+cos(mθ+nϕ)i sin(mθ+nϕ)=2cos(mθ+nϕ)

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