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Question

If x cos θ=y cos (θ+2π3)=z cos(θ+4π3), then the value of 1x+1y+1z is equal to


A

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B

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C

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D

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Solution

The correct option is C


We have

x cos θ=y cos (θ+2π3)=z cos(θ+4π3)=kcos θ=kx, cos(θ+2π3)=kyand cos(θ+4π3)=kzHence kx+ky+kz=cos θ+cos(θ+2π3)+cos(θ+4π3)
=cos θ+cos(π3θ)cos(π3+θ)=cos θ2 cosπ3cos θ=0


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