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B
at x = 0, y = 1, y’ = 0
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C
at x = y = 1, y’ = – 1
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D
at x = 1, y = 0, y’ = 1
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Solution
The correct option is C at x = y = 1, y’ = – 1 xcosy+ycosx=5 ⇒ecosylogex+ecosxlogey=5 ∴ecosylogex{cosyx−logex(siny)dydx}+ecosxlogey{cosxydydx−sinxlogey}=0 Putx=y=1,(cos1−0)+(cos1dydx−0)=0 ∴dydx=−1 ory′=−1