If x - ct and y - c - t- find dy - dx at t -2-A- 1-4- 4- 0D- -1-4

Dydx=dydtdxdt= ct^2c= 1t^2 ∴dydx]_t=2= 14 ...

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Property 4

If x = ct and...

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If $x = c t$ and $y = \frac{c}{t},$ find $\frac{d y}{d x}$ at $t = 2.$

\frac{1}{4}

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\frac{- 1}{4}

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Similar questions

If x=ct and $y = \frac{c}{t}$ , find $\frac{d y}{d x}$ at $t = 2.$

x = c t

y = \frac{c}{t}

\frac{d y}{d x}

t = 2

A :

x = c t, y = \frac{c}{t}

t = 1, \frac{d y}{d x} =

B :

x = 3 cos θ - {cos}^{3} θ, y = 3 sin θ - {sin}^{3} θ

θ = \frac{π}{3}, \frac{d y}{d x} =

C :

x = a (t + \frac{1}{t}), y = a (t - \frac{1}{t})

t = 2, \frac{d y}{d x} =

D :

log (sec x)

tan x

x = \frac{π}{4}

If x=ct and $y = \frac{c}{t}$ , find $\frac{d y}{d x}$ at $t = 2.$

x^{2} + y^{2} = t + \frac{1}{t}

x^{4} + y^{4} = t^{2} + \frac{1}{t^{2}}

\frac{d y}{d x} =

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