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Question

If {x} denotes the fractional part of x, then value of
limx0{x}tan{x} is

A
1
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B
0
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C
1
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D
It does not exist
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Solution

The correct option is D It does not exist
limx0{x}tan{x}
We know, for x0+, {x}=x{x}0
But for x0,{x}=1+x{x}1

LHL=limx0{x}tan{x}=1tan1
RHL=limx0+xtanx=1
Clearly, LHLRHL
Hence, limit does not exist

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