Question

If $x+\frac{1}{x}=2$ then find the value of $x^2+\frac{1}{x^2}$.

Answer 1

Given,

$x+\frac{1}{x}=2$.

Now squaring both sides we get,

$x^2+\frac{1}{x^2}+2=4$

or, $x^2+\frac{1}{x^2}=2$.