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Question

If x−1x=5, find the value of x2+1x2 and x4+1x4.

A
x2+1x2=27,x4+1x4=727
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B
x2+1x2=23,x4+1x4=527
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C
x2+1x2=23,x4+1x4=531
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D
x2+1x2=27,x4+1x4=731
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Solution

The correct option is A x2+1x2=27,x4+1x4=727
(x1x)=5

Squaring on both sides

(x2+1x2)=25+2=27

Squaring on both sides

(x4+1x4)=7292=727

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