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Question

If x1x=6, find the value of :
i) x31x3
ii) x2+1x2

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Solution

It is given that x1x=6

(i)

Cube both sides of the given equation,

(x1x)3=63

x31x33×x×1x(x1x)=216

x31x33(6)=216

x31x318=216

x31x3=234

(ii)

Square both sides of the given equation,

(x1x)2=62

x2+1x22×x×1x=36

x2+1x22=36

x2+1x2=38


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