Question

If $x-\frac{1}{x}=7$, find the values of: $x^2+\frac{1}{x^2}$.

Answer 1

Given, $x-\frac{1}{x}=7$.

Now, squaring both sides we get,

$x^2+\frac{1}{x^2}-2=49$

or, $x^2+\frac{1}{x^2}=51$.