Question

If $x-\frac{1}{x}=7$ then find the value of $x^2+\frac{1}{x^2}.$

Answer 1

We have,

$x-\frac{1}{x}=7$

On squaring both sides, we get

$x^2+\frac{1}{x^2}-2=49$

$x^2+\frac{1}{x^2}=51$

Hence, this is the answer.