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Question

If x=4aba+b, then prove that x+2ax2a+x+2bx2b=2

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Solution

Given: x=4aba+b
x2a=2ba+b
by componendo and dividendo
x+2ax2a=2b+a+b2b(a+b)
x+2ax2a=3b+a(ba)....(i)
again x=4aba+b
x2b=2ba+b
by componendo and dividendo
x+2bx2b=2a+a+b2a(a+b)
x+2bx2b=3a+b(ab)
x+2bx2b=(3a+b)ba....(ii)
On adding (i) and (ii)
x+2ax2a+x+2bx2b=3b+aba(3a+b)(ba)
x+2ax2a+x+2bx2b=3b+a3ab(ba)
x+2ax2a+x+2bx2b=2b2aba
x+2ax2a+x+2bx2b=2(ba)(ba)
x+2ax2a+x+2bx2b=2

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