If x-m-n-2m-n-2 -then formula of m is m-n-2x-1x-1 -

The correct option is A TrueGiven, x=m+n+2m n 2 mx nx 2x=m+n+2 mx m=nx+2x+n+2 m(x 1)=(n+2)(x+1) m=(n+2)(x+1)x 1 ...

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Polynomial Functions

if x=m+n+2m...

Question

if $x = \frac{m + n + 2}{m - n - 2}$ ,then formula of m is $m = \frac{(n + 2) (x + 1)}{x - 1}$ ?

True

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False

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(1 + x)^{n} =^{n} C_{0} +^{n} C_{1} x +^{n} C_{2} x^{2} +^{n} C_{n} x^{n}, x ϵ N

^{n} C_{0} -^{n} C_{1} +^{n} C_{2} - . . . . . . + (- 1)^{m - 1} \times^{n} C_{m - 1}

= (- 1)^{m - 1} \frac{(n - 1) (n - 2) . . (n - m + 1)}{(m - 1)!}

I_{n - m} = \int \frac{s i n^{n} x}{c o s^{m} x} d x

I_{n - m} + \frac{n -, 1}{m - 1} I_{n - 2, 2 - m}

(1 + x)^{n} = C_{0} + C_{1} x + C_{2} x^{2} + \dots + C_{n} x^{n},

n \in N,

2 \leq m \leq n,

C_{0} - C_{1} + C_{2} - \dots + [(- 1)^{m - 1}] C_{m - 1}

\frac{m}{n} x^{2} + \frac{n}{m} = 1 - 2 x

f (x) = \{\begin{cases} m x + 1, & x \leq \frac{π}{2} \\ \sin x + n, & x > \frac{π}{2} \end{cases}

x = \frac{π}{2}

m = \frac{n π}{2} + 1

n = \frac{m π}{2}

m = n = \frac{π}{2}

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