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Question

If x=2+121 and y=212+1, find the value of x2+y2+xy.

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Solution

x2+y2+xy=(2+121)2+(212+1)2+(2+121)(212+1)=2+1+222+122+2+1222+1+22+2121=3+22322+3223+22+1=(3+22322)(3+223+22)+(3223+22)(322322)+1=9+8+12298+9+812298+1=9+8+122+9+8122+1=35

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