If x=√2+1√2−1,y=√2−1√2+1, then x2+xy+y2 is equal to?
A
39
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B
35
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C
38
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D
36
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Solution
The correct option is B35 Letf(x)=x2+xy+y2=(x+y)2−xy−−−−(1)Nowx+y=√2+1√2−1+√2−1√2+1=2+1+2√2+2+1−2√22−1=6∴(x+y)2=36.Againxy=√2+1√2−1×√2−1√2+1=1∴Substitutingfor(x+y)2andxyinf(x)wehavef(x)=36−1=35