If x - -2a - 1 - -2a - 1-2a - 1 - -2a - 1- then show that x2 - 4ax - 1 - 0

[ x = √(2a + 1) #160; + √(2a 1)√(2a + 1) #160; √(2a 1); = ( √(2a + 1) #160 ...

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Monotonically Increasing Functions

If x = √2a ...

Question

If $x = \frac{\sqrt{2 a + 1} + \sqrt{2 a - 1}}{\sqrt{2 a + 1} - \sqrt{2 a - 1}}$ , then show that $x^{2} - 4 a x + 1 = 0$

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