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Question

If x=y0dttt2, then dydx is equal to

A
y
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B
1+y2
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C
y1+y2
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D
y2
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Solution

The correct option is B 1+y2
x=y0dttt2x=y0dt14(t12)2x=[2sin1(2t1)]40x=2sin1(2y1)3πx+3π2=sin1(2y1)y=(sin(x2+3π2)+1)/2y=cos(x2)2+12dx=sin(x/2)4=1+y2

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