If xϵR, the solution set of the equation 4−x+0.5−7.2−x−4<0 is equal to
A
(2,72)
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B
(−2,∞)
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C
(2,∞)
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D
(−∞,∞)
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Solution
The correct option is B(−2,∞) Put 2−x=t and 40.5=412=2 ∴2t2−7t−4<0⇒(t−4)(2t+1)<0 −12<t<4⇒0<2−x<22
or (12)∞<(12)x<(12)−2
Since 12<1∴−2<x<∞ ∴xϵ(−2,∞)⇒(b)