If x - -13 - 59 - 5-4-12 - 5-7- 512- then x3 - -

Given: x = ( 1)^3 × 5^9 × 5^ 4/( 1)^2 × 5^ 7× 5^12 We know that nbsp;a^m × a^n = a^m + n. Now, x = ( 1)^3 × 5^9 × 5^ 4/( 1)^2 × 5^ 7× 5^12 = ( 1)× 5^(9+( 4 ...

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Byju's Answer

Standard VIII

Mathematics

Expanded Form of a Number

If x = -13 × ...

Question

If $x = \frac{(- 1)^{3} \times 5^{9} \times 5^{- 4}}{(- 1)^{2} \times 5^{- 7} \times 5^{12}}$ , then $x^{3}$ = .

-1

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Solution

The correct option is A -1
Given: $x = \frac{(- 1)^{3} \times 5^{9} \times 5^{- 4}}{(- 1)^{2} \times 5^{- 7} \times 5^{12}}$
We know that $a^{m} \times a^{n} = a^{m + n}$ .

Now, $x = \frac{(- 1)^{3} \times 5^{9} \times 5^{- 4}}{(- 1)^{2} \times 5^{- 7} \times 5^{12}}$
$= \frac{(- 1) \times 5^{(9 + (- 4))}}{1 \times 5^{- 7 + 12}}$
$= \frac{(- 1) \times 5^{5}}{5^{5}} = - 1$
Here, $x = - 1$ .
Then, $x^{3} = (- 1)^{3} = - 1$ .

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Similar questions

Q. If

x = \frac{(- 1)^{3} \times 5^{9} \times 5^{- 4}}{(- 1)^{2} \times 5^{- 7} \times 5^{12}}

, then

x^{3}

= .

Q. If

x = \frac{(- 1)^{3} \times 5^{9} \times 5^{- 4}}{(- 1)^{2} \times 5^{- 7} \times 5^{12}}

, then

x^{3}

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Q. If

(4 + \sqrt{13}) \times (5 - \sqrt{13}) \times (7 - \sqrt{13}) =

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Q.
If

7 - \frac{x^{2}}{12} \leq f (x) \leq 7 + \frac{x^{3}}{5}

for all

x \neq 0

, then

lim x \to 0 f (x) =

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

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If x=(−1)3×59×5−4(−1)2×5−7×512, then x3 = .

The correct option is A -1Given: x=(−1)3×59×5−4(−1)2×5−7×512 We know that am×an=am+n. Now, x=(−1)3×59×5−4(−1)2×5−7×512 =(−1)×5(9+(−4))1×5−7+12 =(−1)×5555=−1 Here, x=−1. Then, x3=(−1)3=−1.

If $x = \frac{(- 1)^{3} \times 5^{9} \times 5^{- 4}}{(- 1)^{2} \times 5^{- 7} \times 5^{12}}$ , then $x^{3}$ = .