Question

If $x+\frac{1}{x}=1$, then the value of $x^2+\frac{1}{x^2}$ will be:

• A. Zero
• B. positive
• C. negative
• D. can be positive or negative

Answer 1

The correct option is C negative

$x+\frac{1}{x}=1$
$(x+\frac{1}{x}{)}^2=1$
$x^2+\frac{1}{x^2}+2=1$
$x^2+\frac{1}{x^2}=-1$