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Sum of Infinite Terms of a GP

If x+1/x = 2,...

Question

If $x + \frac{1}{x} = 2$ , then $x^{6} + \frac{1}{x^{6}} =$ ______ .
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Solution

The correct option is A 2

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x^{3 / 2} + x^{- 3 / 2} = 3

, then the value of

x^{6} + \frac{1}{x^{6}}

x + \frac{1}{x} = 2 cos θ

x^{6} - \frac{1}{x^{6}}

x + \frac{1}{x} = 3

, then the value of

x^{6} + \frac{1}{x^{6}}

x + \frac{1}{x} = 3

then the value of

x^{6} + \frac{1}{x^{6}}

lim x \to - \infty (\sqrt{x^{6} + a x^{5} + b x^{3} - c x + d -} \sqrt{x^{6} - 2 x^{5} + x^{3} + x + 1}) = 2

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Sum of Infinite Terms of a GP

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