If x-1-x-2thenx8-1-x8-A- 0B- 2C- 4D- 8

The correct option is B 2 ⇒ x + 1/x = 2 ⇒ x^2 2x + 1= 0 ⇒ (x 1)^2 = 0 ⇒ (x 1) = 0 ⇒ x = 1 Substituting the value of x , we get ⇒ x^8 + 1/x^8 = 1 + 1 = 2 ...

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Standard VIII

Mathematics

Expansion of (x-y)^2

If x+1/x=2the...

Question

If $x + \frac{1}{x} = 2$

then

$x^{8} + \frac{1}{x^{8}} = ?$

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Solution

The correct option is C
2

$\Rightarrow x + \frac{1}{x} = 2$

$\Rightarrow x^{2} - 2 x + 1 = 0$

$\Rightarrow (x - 1)^{2} = 0$

$\Rightarrow (x - 1) = 0$

$\Rightarrow x = 1$

Substituting the value of $x$ , we get

$\Rightarrow x^{8} + \frac{1}{x^{8}} = 1 + 1 = 2$

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If x+1x=2 then x8+1x8=?

The correct option is C 2 ⇒x+1x=2 ⇒x2−2x+1=0 ⇒(x−1)2=0 ⇒(x−1)=0 ⇒x=1 Substituting the value of x , we get ⇒x8+1x8=1+1=2

If $x + \frac{1}{x} = 2$

then

$x^{8} + \frac{1}{x^{8}} = ?$

The correct option is C
2

$\Rightarrow x + \frac{1}{x} = 2$

$\Rightarrow x^{2} - 2 x + 1 = 0$

$\Rightarrow (x - 1)^{2} = 0$

$\Rightarrow (x - 1) = 0$

$\Rightarrow x = 1$

Substituting the value of $x$ , we get

$\Rightarrow x^{8} + \frac{1}{x^{8}} = 1 + 1 = 2$