If x - 1 - x - 4- find the value of x 4 - 1 - x 4-

x+1x=4 (x+1x)^2=16 x^2+1x^2+2=16 x^2+1x^2=14 (x^2+1x^2)^2=196 x^4+1x^4+2=196 x^4+1x^4=194 ...

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(a + b)^2 Expansion and Visualisation

If x + 1 / ...

Question

If $x + \frac{1}{x} = 4$ , find the value of $x^{4} + \frac{1}{x^{4}}$ .

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Solution

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x + \frac{1}{x} = 3

x^{4} + \frac{1}{x^{4}}

x - \frac{1}{x} = 8

x^{4} + \frac{1}{x^{4}}

(x - \frac{1}{x}) = 5

(x^{4} + \frac{1}{x^{4}})

If $(x + \frac{1}{x}) = 4$ , find the value of
(i) If $(x^{2} + \frac{1}{x^{2}})$ and
(ii) $(x^{4} + \frac{1}{x^{4}})$

x - \frac{1}{x} = 5,

x^{4} + \frac{1}{x^{4}}

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