If x2-3-7 x1-3-10-0- then x-

The correct option is A 125, 8 Given that x^2/3 7x^1/3+10 =0. Given equation can be written as (x^1/3)^2 7(x^1/3) + 10 = 0 Let a = x^1/3, then it reduces to ...

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Byju's Answer

Standard VII

Mathematics

Exponents with Like Bases

If x2/3-7 x1/...

Question

If $x^{\frac{2}{3}} - 7 x^{\frac{1}{3}} + 10 = 0$ , then x =

{125}

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{8}

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{125, 8}

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Solution

The correct option is D
{125, 8}

Given that $x^{\frac{2}{3}} - 7 x^{\frac{1}{3}} + 10 = 0$ .

Given equation can be written as $(x^{\frac{1}{3}})^{2} - 7 (x^{\frac{1}{3}}) + 10 = 0$

Let $a = x^{\frac{1}{3}}$ , then it reduces to the equation

$a^{2} - 7 a + 10 = 0$ ⇒ (a - 5)(a - 2) = 0 ⇒ a = 5, 2

Putting these values, we have $a^{3} = x$ ⇒ $x$ = 125 and 8

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If x23−7x13+10=0, then x =

The correct option is D {125, 8} Given that x23−7x13+10=0. Given equation can be written as (x13)2−7(x13)+10=0 Let a=x13, then it reduces to the equation a2−7a+10=0 ⇒ (a - 5)(a - 2) = 0 ⇒ a = 5, 2 Putting these values, we have a3=x ⇒ x = 125 and 8

If $x^{\frac{2}{3}} - 7 x^{\frac{1}{3}} + 10 = 0$ , then x =