If x - b - b 2-4 ac -2 a- then express the given formula in terms of a-A- x-c - x-4 bB- c - x -4 b - xC- - c - x -4 bx - xD- -c-x b - x2

The correct option is D ( c + xb )/x2 x = b + √(b^2 4ac)/2a (2ax + b) = √(b^2 4ac) (2ax + b)^2 = (b^2 4ac) (Squaring both sides) 4 a^2x^2 + b^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Range

If x =- b +√ ...

Question

If x = $\frac{- b + \sqrt{b^{2} - 4 a c}}{2 a}$ , then express the given formula in terms of a.

x(-c/x – 4b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(c/x – 4b)/x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(-c/x – 4bx)/x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- ( c + xb)/x²

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

x = $\frac{- b + \sqrt{b^{2} - 4 a c}}{2 a}$ , then express the given formula in terms of b.

If b² – 4ac = 0 then The roots of the Quadratic equation ax² + bx + c = 0 are given by :

x = \frac{- b + \sqrt{b^{2} - 4 a c}}{2 a}

\frac{(X^{a + b})^{2} \times (X^{b + c})^{2} \times (X^{c + a})^{2}}{(X^{a} X^{b} X^{c})^{4}}

x = 2, a = 1, b = 2, c = 3

y = \frac{a x^{2}}{(x - a) (x - b) (x - c)} + \frac{b x}{(x - b) (x - c)} + \frac{c}{x - c} + 1,

\frac{y^{'}}{y}

(Here, y^{'} = \frac{d y}{d x})

Join BYJU'S Learning Program