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Quantitative Aptitude

Quadratic Equations

If x=√3+1/√3-...

Question

If $x = \frac{\sqrt{3} + 1}{\sqrt{3} - 1} a n d y = \frac{\sqrt{3} - 1}{\sqrt{3} + 1}, t h e n t h e v a l u e o f (x^{2} + y^{2}) i s :$

A

13

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B

14

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C

15

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D

16

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Solution

The correct option is B
14

$x = (2 + \sqrt{3})$ $y = (2 - \sqrt{3})$ x $^{2}$ + y $^{2}$ = 14

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28

Similar questions

x = \frac{\sqrt{3} + 1}{\sqrt{3} - 1}

y = \frac{\sqrt{3} - 1}{\sqrt{3} + 1}

x^{2} + y^{2}

x = \frac{\sqrt{3} + 1}{\sqrt{3} - 1}

y = \frac{\sqrt{3} - 1}{\sqrt{3} + 1}

find the value of

x^{2} + x y + y^{2}

Q. The value of

\frac{1}{x^{2}} + \frac{1}{y^{2}}

x = 2 + \sqrt{3}

y = 2 - \sqrt{3}

x = \sqrt{3} + \sqrt{2}

y = \frac{1}{\sqrt{3} + \sqrt{2}}

then find the value of

(x + y)^{2} + (x - y)^{2}

x = \sqrt[3]{28}, y = \sqrt[3]{27}

, then the value of

x + y - \frac{1}{x^{2} + x y + y^{2}}

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