If x=√3+1√3−1andy=√3−1√3+1,thenthevalueof(x2+y2)is:
10
13
14
15
16
x=(2+√3) y=(2−√3) x2 + y2 = 14
If x=3+2√2,thenthevalueof(√x+1√x) is:
if X=2√3+22√3−2 and
Y=2√3−22√3+2
Find X2+Y2−XYX2+Y2+XY
The area bounded by the curve y2 = 16x, x = 1, x = 3 and X-axis is: