Question

# If x g of MnO2 and the volume of HCl of specific gravity 1.2g mL−3 and 5% by weight needed to produce 1.12L of Cl2 at STP by the reaction,MnO2+4HCl→MnCl2+3H2O+Cl2then value of 100X is :

A
435
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
450
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
400
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 435(a) NHCl=% by weight×10×dEwofHCl=5×10×1.236.5=1.64Now, mEq of MnO2= mEq of HCl=mEq of Cl2 formed.=1.1211.2×103=100 ⎡⎣EwofCl2=M21eqofCl2=11.2L⎤⎦(b) Volume of HCl used:N×V=1001.64×V=100∴VHCl=60.97mLBecause HCl is also used to give MnCl2 thus volume used is double than required for the reduction of MnO2.∴VHCl=2×60.97=121.94mL(c) Also, mEq of MnO2=mEq of HCl=100W87/2×103=100(Ew of MnO2=55+322)∴WMnO2=4.35g

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Water - Hardness and Treatment
CHEMISTRY
Watch in App
Join BYJU'S Learning Program