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Byju's Answer

Standard XII

Chemistry

Concentration Terms

If x g weig...

Question

If $x$ g weight of $H_{2} S O_{4}$ is present in $1200$ mL of a solution of $0.2 N$ strength, then the value of $100 x$ is:

1176

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1200

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1125

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none of the above

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Solution

The correct option is A $1176$
Molecular weight of $H_{2} S O_{4} = 2 \times 1 + 32 + 16 \times 4 = 98$ g/mol

Equivalent weight $= \frac{98}{2} = 49$

$N = \frac{W_{2} \times 1000}{E w_{2} \times V_{s o l} (in mL)}$ $⟹ 0.2 = \frac{W_{2} \times 1000}{49 \times 1200} \Rightarrow W_{2} = 11.76$ g

Hence, the value of $100 x$ is $1176$ .

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If x g weight of H2SO4 is present in 1200 mL of a solution of 0.2 N strength, then the value of 100x is:

The correct option is A 1176Molecular weight of H2SO4=2×1+32+16×4=98 g/molEquivalent weight =982=49N=W2×1000Ew2×Vsol(in mL) ⟹0.2=W2×100049×1200⇒W2=11.76 gHence, the value of 100x is 1176.

If $x$ g weight of $H_{2} S O_{4}$ is present in $1200$ mL of a solution of $0.2 N$ strength, then the value of $100 x$ is: