If $x_{i}$ are the mid-points of the class intervals of grouped data, $f_{i}$ are the corresponding frequencies and $¯ x$ is the mean, then $\sum f_{i} (x_{i} - ¯ x)$ is equal to ____.

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Solution

The correct option is B
0

$∵ ¯ x = \frac{\sum f_{i} x_{i}}{n} ⟹ \sum f_{i} x_{i} = n ¯ x N o w, \sum f_{i} (x_{i} - ¯ x) = \sum f_{i} x_{i} - \sum f_{i} ¯ x = n ¯ x - n ¯ x [∵ \sum f_{i} = n] = 0$

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Q. If x_i' s are the midpoints of the class intervals of a grouped data, f_i' s are the corresponding frequency and

x

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is the mean, then

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Q. Question 3
If

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If $x_{i}$ are the mid-points of the class intervals of grouped data, $f_{i}$ are the corresponding frequencies and $¯ x$ is the mean, then $\sum f_{i} (x_{i} - ¯ x)$ is equal to ____.

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If xi are the mid-points of the class intervals of grouped data, fi are the corresponding frequencies and ¯x is the mean, then ∑fi(xi−¯x) is equal to ____.

The correct option is B 0 ∵¯x=∑fixin⟹∑fixi=n¯xNow,∑fi(xi−¯x)=∑fixi−∑fi¯x =n¯x−n¯x[∵∑fi=n] =0

If $x_{i}$ are the mid-points of the class intervals of grouped data, $f_{i}$ are the corresponding frequencies and $¯ x$ is the mean, then $\sum f_{i} (x_{i} - ¯ x)$ is equal to ____.

The correct option is B
0

$∵ ¯ x = \frac{\sum f_{i} x_{i}}{n} ⟹ \sum f_{i} x_{i} = n ¯ x N o w, \sum f_{i} (x_{i} - ¯ x) = \sum f_{i} x_{i} - \sum f_{i} ¯ x = n ¯ x - n ¯ x [∵ \sum f_{i} = n] = 0$