CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x[0,2π], then the number of solutions of the equation 81cos2x+81sin2x=30 is

Open in App
Solution

81cos2x+81sin2x=30
81sin2x+811sin2x=30
81sin2x+8181sin2x=30
Let 81sin2x=t
Then t+81t=30
t230t+81=0
(t3)(t27)=0
t=3,27

81sin2x=3 and 81sin2x=27
34sin2x=31 and 34sin2x=33
sin2x=14 and sin2x=34
sinx=±12 and sinx=±32

Since x[0,2π],
x=π6,5π6,7π6,11π6,π3,2π3,4π3,5π3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon