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Question

If x[4,1], then 1x2+4x+7 belongs to

A
[17,)
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B
(,17][13,)
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C
[17,1)
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D
[17,13]
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Solution

The correct option is D [17,13]
Here, x[4,1]
x2+4x+7=(x+2)2+3
It will be minimum at x=2 and maximum at x=4
(x+2)2+3[3,7]
Since, (3)(7)>0
So, 1x2+4x+7[17,13]

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