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Question

If xR, the solution set of the in-equation 4x+0.57×2x4<0 is equal to

A
(2,72)
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B
(2,)
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C
(2,)
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D
(,)
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Solution

The correct option is B (2,)
4x+0.57×2x4<02×22x7×2x4<0
2×22x8×2x+2x4<0
(2x4)(2×2x+1)<0
12<2x<4
since 2x>0 therefore 0<2x<4
2<x<

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