if X + iota Y is equal to 3 upon 2 + cos theta + iota sin theta then the value of x square + Y square is

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x {sin}^{3} θ + y {cos}^{3} θ = sin θ cos θ

x sin θ = y cos θ,

(x^{2} + y^{2})

ι, ι_{2} a n d ι_{3}

ι_{1} a n d ι_{2}

ι_{2} a n d ι_{3}

x = 2 cos θ - sin θ; y = cos θ - 3 sin θ,

(3 x - y)^{2} + (x - 2 y)^{2}

x {sin}^{3} θ + y {cos}^{3} θ = sin θ cos θ

x sin θ = y cos θ

x^{2} + y^{2}

x {sin}^{3} θ + y {cos}^{3} θ = sin θ cos θ

x sin θ = y cos θ

x^{2} + y^{2} = 1

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