If X is a 2×3 matrix such that ∣∣XTX∣∣≠0 and A=I2−X(XTX)−1XT then A2 is equal to: (XT denotes transpose of matrix X)
A
A
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B
I
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C
A−1
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D
AX
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Solution
The correct option is BA By property of inverse, (AB)−1=B−1A−1 So,A=I2−X(XTX)−1XT ⇒A=I2−XX−1(XT)−1XT A=I2−(I2)(I2) (because MM−1=I=M−1MandI2=[1001]) So,A=I2−I22=[0000] So,A2=A